Created By : Abhinandan Kumar

Reviewed By : Rajashekhar Valipishetty

Last Updated : May 30, 2023


Enter the Base (a)

Enter the Base (b)

Enter the Base (c)


Area of Triangle 41 inches, 36 inches and 64 inches is 682.9230832 inches.

The area of a triangle is defined as the total space that is enclosed by any particular triangle. The basic formula to find the area of a given triangle is A = 1/4 × √((a + b + c) x (-a + b + c) x (a - b + c) x (a + b - c)), where a,b,c are the bases of the given triangle. Area of Triangle 41 inches, 36 inches and 64 inches is 682.9230832 inches.


    Area of Triangle side (a) 41 in by side (b) 36 in by side (c) 64 in in other units

Value unit
0.0173462 km2
0.0107785 mi2
17.3462463 m2
56.9102569 ft2
682.9230832 in2
18.9700856 yd2
1734.6246313 cm2
17346.2463133 mm2

Steps:

Given that side (a) = 41 in and side (b) =36 in and side (c) = 64 in

Area = 1/4 √((a+b+c)*(-a+b+c)*(a-b+c)*(a+b-c))

Put the value of a,b and c value in Area Formula.

Area = 1/4 √((41 + 36 + 64)*(-41 + 36 + 64)*(41-36+64)*(41 + 36 - 64))

Simplify the above exception

Area = 682.9230832 in2

∴ Area of Triangle side (a) 41 in by side (b) 36 in by side (c) 64 in is 682.9230832 in2